Topic 3.11: Spectroscopy and the Electromagnetic Spectrum Quiz

Master AP Chemistry Topic 3.11 with this free practice quiz. Test your skills on microwave spectroscopy, infrared spectroscopy, and uv vis spectroscopy to prepare for your AP exam.

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Spectroscopy and the Electromagnetic Spectrum Quiz

18 MCQs

Master the electromagnetic spectrum with these 18 MCQs on AP Chemistry Topic 3.11: Spectroscopy and the Electromagnetic Spectrum.

Covered Subtopics: Electromagnetic spectrum regions, Wave properties of radiation, Photon energy, Interaction of radiation with matter

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1. Which statement correctly describes the relationship between wavelength and frequency for electromagnetic radiation?

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2. Which one consists of photons with the greatest energy? Radiation 1: λ = 1.0 × 10⁻³ m; Radiation 2: λ = 5.0 × 10⁻⁷ m; Radiation 3: ν = 3.0 × 10¹⁸ Hz; Radiation 4: ν = 1.0 × 10¹² Hz

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3. Electromagnetic radiation with a frequency of 6.0 × 10¹⁴ Hz is detected. Which region of the spectrum does it belong to?

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4. Spectroscopy is best defined as

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5. A sample absorbs strongly at 600 nm but does not absorb at 900 nm. A chemist concludes the sample appears blue-green to the eye. Which concept from spectroscopy best supports identifying a substance by the wavelengths it absorbs?

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6. Infrared radiation is strongly associated with which molecular process?

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7. Light of wavelength 4.00 × 10⁻⁷ m and light of wavelength 8.00 × 10⁻⁷ m shine on the same sample. What is the ratio of the energy of one photon of the shorter-wavelength light to the energy of one photon of the longer-wavelength light?

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8. A particle diagram shows two waves. Wave P completes 2 full cycles in a given distance, while wave Q completes 6 full cycles in the same distance. Which statement correctly compares the two waves?

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9. Which region of the electromagnetic spectrum has the longest wavelength?

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10. The energy of one mole of photons of wavelength 5.00 × 10⁻⁷ m is closest to which value? (h = 6.626 × 10⁻³⁴ J·s, c = 3.00 × 10⁸ m/s, Avogadro's number = 6.022 × 10²³ mol⁻¹)

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11. Two waves of electromagnetic radiation travel through a vacuum. Wave X has a wavelength of 700 nm and wave Y has a wavelength of 400 nm. Which statement is correct?

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12. A scientist measures the wavelength of radiation from three sources: source A emits at 3.0 × 10⁻⁹ m, source B emits at 3.0 × 10⁻⁶ m, and source C emits at 3.0 × 10⁻³ m. Which ranking orders the sources from lowest to highest frequency?

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13. Which of the following correctly matches each type of radiation to a common application or source?

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14. Which wavelength range corresponds approximately to visible light?

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15. Which of the following best explains why ultraviolet light can cause sunburn but visible light of the same intensity cannot?

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16. Which of the following is a valid conclusion from the relationships c = λν and E = hν?

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17. Which of the following lists the regions of the electromagnetic spectrum in order of increasing energy per photon?

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18. A photon of green light has a wavelength of 5.00 × 10⁻⁷ m. What is the energy of one photon of this light? (h = 6.626 × 10⁻³⁴ J·s, c = 3.00 × 10⁸ m/s)

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The Spectrum, in Order

All electromagnetic radiation travels at c = 3.00 × 10⁸ m/s in a vacuum. Ordered from longest wavelength to shortest: radio, microwave, infrared, visible, ultraviolet, X-ray, gamma.

Frequency and photon energy run in the opposite direction to wavelength. Radio waves have the longest wavelength, the lowest frequency and the weakest photons. Gamma rays have the shortest wavelength, the highest frequency and the most energetic photons.

Visible light is a narrow slice in the middle, roughly 400 nm to 700 nm. Violet (~400 nm) is the high energy end; red (~700 nm) is the low energy end. Anything just below 400 nm is ultraviolet, anything just above 700 nm is infrared.

The Two Equations

c = λν

Wavelength λ (in metres) times frequency ν (in s⁻¹, also written Hz) equals the speed of light. Because c is fixed, λ and ν are locked in inverse proportion: halve the wavelength and the frequency doubles.

E = hν = hc/λ

A photon’s energy is E = hν, where h is Planck’s constant, 6.626 × 10⁻³⁴ J·s. Substituting ν = c/λ gives E = hc/λ, the form you will use most, because spectra are reported in wavelengths. Energy rises as wavelength falls.

Two consequences worth fixing in memory. Photon energies are tiny, around 10⁻¹⁹ J for visible light, so questions often ask for energy per mole instead: multiply by Avogadro’s number, 6.022 × 10²³. And the product hc is a constant, 1.986 × 10⁻²⁵ J·m, which speeds up every E = hc/λ calculation.

What Each Region Does to Matter

The region of the spectrum tells you what kind of change the radiation causes. This matching is a favourite AP question.

Microwave radiation is absorbed by molecules rotating. The photon energy is small, enough only to change rotational states.

Infrared radiation makes bonds vibrate, stretching and bending. Each type of bond absorbs at characteristic frequencies, which is why IR spectra are used to identify the bonds and functional groups present in a sample.

Ultraviolet and visible radiation move electrons between energy levels. Absorbing a photon promotes an electron to a higher level; when the electron falls back, it emits a photon with exactly the energy of the gap.

That last point explains line spectra. Electron energy levels are quantized, so only certain gaps exist, and each gap gives one line of one specific colour or wavelength. Every element has its own set of gaps, so every element’s emission spectrum is a unique fingerprint.

Worked Examples

Example 1: photon energy at 450 nm

E = hc/λ = (6.626 × 10⁻³⁴ × 3.00 × 10⁸) / (450 × 10⁻⁹) = 4.42 × 10⁻¹⁹ J per photon.

Per mole: 4.42 × 10⁻¹⁹ × 6.022 × 10²³ = 2.66 × 10⁵ J/mol, or 266 kJ/mol. Blue light therefore carries enough energy per mole to matter chemically, unlike radio waves, whose photons are millions of times weaker.

Example 2: from energy back to wavelength

An electron transition emits a photon of 3.03 × 10⁻¹⁹ J. Find the wavelength and the colour.

λ = hc/E = (1.986 × 10⁻²⁵) / (3.03 × 10⁻¹⁹) = 6.56 × 10⁻⁷ m = 656 nm.

656 nm sits in the red part of the visible spectrum. This is in fact hydrogen’s red emission line, the gap between its third and second energy levels.

Traps Specific to This Topic

Forgetting the nanometre conversion is the costliest error here. If λ is given in nm, convert to metres (× 10⁻⁹) before using either equation, or your answer is out by a factor of 10⁹.

Read whether the question wants energy per photon or per mole. They differ by a factor of 6.022 × 10²³, and both versions appear as answer options.

Longer wavelength means lower energy, never higher. When a question asks you to rank radiations by energy, reverse the wavelength order.

Emission and absorption involve the same gap, so the photon has the same energy either way. Falling electrons emit; rising electrons absorb. Direction questions test exactly this.

Frequency is never measured in metres and wavelength never in s⁻¹. If your calculated ν comes out in anything but s⁻¹, a unit conversion has gone wrong upstream.

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